```{include} /../core/dataserver/attribute/introducing_tstochastic_attribute/uniform_by_part_equation.md
```

For this distribution, the mean value is $\mu = 0.25 * (x_{\rm max} + x_{\rm min} + 2 x_{\rm med})$ 
while the variance is $\sigma^2 = \frac{1}{6} * (x^2_{\rm max} + x^2_{\rm min} + x_{\rm med} 
( x_{\rm max} + x_{\rm min} + 2 x_{\rm med}))$.

```{include} /../core/dataserver/attribute/introducing_tstochastic_attribute/uniform_by_part_figure.md
```